tolong dibantu menggunakan cara,besok dikumpulkan
Penjelasan dengan langkah-langkah:
Segitiga DAB
[tex]DA^{2}+AB^{2}=BD^{2}\\ \\ 3^{2}+ 4^{2} = BD^{2}\\ \\ 9+16 = BD^{2}\\ \\25 = BD^{2}\\ \\BD = 5cm[/tex]
Segitiga DBC
[tex]BC=\sqrt{CD^{2}-BD^{2}}\\ \\ BC= \sqrt{13^{2}-5^{2} }\\ \\BC = \sqrt{169-25} \\\\BC = \sqrt{144} \\\\BC = 12cm[/tex]
Jawaban:
25 = DB²
DB = √25
DB = 5
Jadi :
BC² = 13² - 5²
BC² = (13 × 13) - (5 × 5)
BC² = 169 - 25
BC² = 144
BC = √144
BC = 12 Cm
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